answer:First, we need to determine the total weight of onions carried per trip. Since each bag weighs 50 kgs and the pickup carries ten bags per trip, the total weight carried per trip is: 10 bags/trip * 50 kgs/bag = 500 kgs/trip Now, we know the total weight of onions harvested is 10000 kgs. To find out how many trips the pickup made, we divide the total weight of onions by the weight carried per trip: 10000 kgs / 500 kgs/trip = 20 trips Therefore, the pickup made boxed{20} trips to transport the entire harvest.

answer:First, we need to convert the speed of the train from kilometers per hour (kmph) to meters per second (m/s) because the lengths of the train and the bridge are given in meters. The conversion factor between kmph and m/s is: 1 kmph = 1000 meters / 3600 seconds So, the speed of the train in m/s is: 42 kmph * (1000 m / 3600 s) = 42 * (10/36) m/s = 11.67 m/s (approximately) The total distance the train needs to cover to completely cross the bridge is the length of the train plus the length of the bridge: 100 meters (train length) + 150 meters (bridge length) = 250 meters Now, we can calculate the time it will take for the train to cross the bridge by dividing the total distance by the speed of the train: Time = Distance / Speed Time = 250 meters / 11.67 m/s ≈ 21.42 seconds Therefore, it will take approximately boxed{21.42} seconds for the train to cross the bridge.

answer:Butanoic acid, also known as butyric acid, has the chemical formula C4H8O2. To find the mass percentage of oxygen (O) in butanoic acid, we need to calculate the total mass of oxygen in the molecule and divide it by the molar mass of butanoic acid. First, let's find the molar mass of butanoic acid: - Carbon (C) has an atomic mass of approximately 12.01 g/mol. - Hydrogen (H) has an atomic mass of approximately 1.008 g/mol. - Oxygen (O) has an atomic mass of approximately 16.00 g/mol. The molar mass of butanoic acid is calculated as follows: Molar mass of C4H8O2 = (4 x 12.01 g/mol) + (8 x 1.008 g/mol) + (2 x 16.00 g/mol) Molar mass of C4H8O2 = (48.04 g/mol) + (8.064 g/mol) + (32.00 g/mol) Molar mass of C4H8O2 = 88.104 g/mol Now, let's calculate the total mass of oxygen in the molecule: Mass of oxygen in C4H8O2 = 2 x 16.00 g/mol = 32.00 g/mol Finally, we can find the mass percentage of oxygen in butanoic acid: Mass percentage of O = (Mass of oxygen / Molar mass of butanoic acid) x 100% Mass percentage of O = (32.00 g/mol / 88.104 g/mol) x 100% Mass percentage of O ≈ 36.32% Therefore, the mass percentage of oxygen in butanoic acid is approximately boxed{36.32%} .

answer:Using the distributive property and combining like terms: [ y(4y^2 - 3) - 6(y^2 - 3y + 8) = 4y^3 - 3y - 6y^2 + 18y - 48 ] Combine like terms: [ 4y^3 - 6y^2 + 15y - 48 ] Thus, the simplified expression is: [ boxed{4y^3 - 6y^2 + 15y - 48} ]