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question:A stemandleaf plot shows the duration of different video clips related to educational content, recorded in minutes and seconds. Each of these clips is from one of 15 different subjects. In the stemandleaf plot, 3 15 represents 3 minutes, 15 seconds, which is the same as 195 seconds. What is the median duration of these video clips? Express your answer in seconds. begin{tabular}{c|ccccc} 1&10&35&45&& 2&05&12&30&50&58 3&15&25&40&55& 4&05&20&&& 5&00&&&& end{tabular}

answer:The total number of video clips is 15, so the median clip duration will be the eighth clip when ordered by duration. From the stem-and-leaf plot: - The durations in seconds are: 70, 95, 105, 132, 150, 170, 198, 205, 220, 240, 255, 270, 300, 320, 360. The 8th duration in this ordered list is 205 seconds (from entry 3 25). Thus, the median duration of these video clips is boxed{205} seconds.

question:A wheel with a diameter of 10 cm makes a certain number of revolutions to cover a specific distance. If it takes 19.108280254777068 revolutions to cover that distance, how long is the distance in centimeters?

answer:To find the distance covered by the wheel, we need to calculate the circumference of the wheel and then multiply it by the number of revolutions. The circumference (C) of a circle (or wheel) is given by the formula: [ C = pi times d ] where ( d ) is the diameter of the wheel. Given that the diameter (d) of the wheel is 10 cm, we can calculate the circumference as follows: [ C = pi times 10 text{ cm} ] Now, to find the total distance covered by the wheel after 19.108280254777068 revolutions, we multiply the circumference by the number of revolutions: [ text{Distance} = C times text{Number of Revolutions} ] [ text{Distance} = (pi times 10 text{ cm}) times 19.108280254777068 ] Using the value of ( pi ) as approximately 3.14159, we get: [ text{Distance} = (3.14159 times 10 text{ cm}) times 19.108280254777068 ] [ text{Distance} = (31.4159 text{ cm}) times 19.108280254777068 ] [ text{Distance} = 600.0000000000001 text{ cm} ] So, the distance covered by the wheel is approximately boxed{600} cm.

question:kamal purchased some kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. He paid 1195 to the shopkeeper. How many kg of grapes did he purchase?

answer:Let's denote the number of kilograms of grapes Harkamal purchased as ( G ). The cost of the grapes is ( 70 ) per kg, so the total cost for the grapes is ( 70G ). The cost of the mangoes is ( 55 ) per kg, and Harkamal bought ( 9 ) kg of mangoes, so the total cost for the mangoes is ( 55 times 9 ). Harkamal paid a total of ( 1195 ) for both the grapes and the mangoes, so we can write the equation: [ 70G + 55 times 9 = 1195 ] Now, let's solve for ( G ): [ 70G + 495 = 1195 ] Subtract ( 495 ) from both sides of the equation: [ 70G = 1195 - 495 ] [ 70G = 700 ] Now, divide both sides by ( 70 ) to find ( G ): [ G = frac{700}{70} ] [ G = 10 ] Harkamal purchased ( boxed{10} ) kg of grapes.

question:A train of a certain length crosses an electric pole in 7.999360051195905 seconds, with its speed being 144 km/hr. How long is the train?

answer:To find the length of the train, we need to convert the speed from km/hr to m/s and then multiply it by the time it takes to cross the electric pole. First, let's convert the speed from km/hr to m/s: Speed in m/s = Speed in km/hr * (1000 m / 1 km) * (1 hr / 3600 s) Speed in m/s = 144 km/hr * (1000 m / 1 km) * (1 hr / 3600 s) Speed in m/s = 144 * 1000 / 3600 Speed in m/s = 144000 / 3600 Speed in m/s = 40 m/s Now that we have the speed in m/s, we can calculate the length of the train by multiplying the speed by the time it takes to cross the electric pole: Length of the train = Speed in m/s * Time in seconds Length of the train = 40 m/s * 7.999360051195905 s Length of the train = 319.9744020478362 m Therefore, the length of the train is approximately boxed{319.97} meters.

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