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question:Expand (x+10)(2y+10).
answer:(x+10)(2y+10) Using the distributive property, we have x(2y+10) + 10(2y+10) Simplifying, we get 2xy+10x+20y+100 So the expanded form is boxed{2xy+10x+20y+100}The answer is: 2xy+10x+20y+100
question:f Beatrice purchased a total of 20 books at the supermarket, where the first 5 books cost 20 each and there is a 2 discount for each additional book purchased, what is the total amount she paid at the supermarket?
answer:The first 5 books cost 20 each, so she paid 5 * 20 = <<5*20=100>>100 for those books. For the remaining 15 books, there is a 2 discount for each book, so she paid 2 less for each book. Therefore, the total discount for the remaining books is 15 * 2 = <<15*2=30>>30. So, the total amount she paid for the remaining books is 15 * (20 - 2) = <<15*(20-2)=270>>270. Therefore, the total amount she paid at the supermarket is 100 + 270 = <<100+270=370>>370. 370 The answer is: 370
question:Mr. Johnson is organizing the school Christmas play and needs x volunteers to help with decorating the auditorium. 5 students from each of the school’s 6 math classes have volunteered to help. 13 teachers have also volunteered to help. How many more volunteers will Mr. Johnson need? If we know the answer to the above question is 7, what is the value of unknown variable x?
answer:We know that 5 students from each of the school's 6 math classes have volunteered to help, which means a total of 5 * 6 = 30 students have volunteered. We also know that 13 teachers have volunteered to help. The total number of volunteers from the students and teachers is 30 + 13 = 43. Mr. Johnson needs x volunteers to help with decorating the auditorium. To find out how many more volunteers Mr. Johnson will need, we can subtract the number of volunteers from the total number of volunteers needed: x - 43. We are given that Mr. Johnson will need 7 more volunteers, so we can write: x - 43 = 7. Solving for x, we get: x = 50. The value of x is 50. 50 The answer is: 50
question:a restaurant, the chef prepared 17 meals to sell for lunch. During lunch, he sold 12 meals. After lunch, the chef prepared another x meals for dinner. How many meals does the chef have for dinner, assuming he can use the remaining lunch meals as well? If we know the answer to the above question is 10, what is the value of unknown variable x?
answer:The chef prepared 17 meals for lunch and sold 12 meals, so he has 17 - 12 = 5 meals remaining from lunch. He also prepared x meals for dinner. The total number of meals the chef has for dinner is the sum of the remaining lunch meals and the dinner meals: 5 + x. We are given that the total number of dinner meals is 10, so we can write: 5 + x = 10. Solving for x, we get: x = 5. The value of x is 5. 5 The answer is: 5